3-3u^2/u^2-5u+4

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Solution for 3-3u^2/u^2-5u+4 equation: 


D( u )

u^2 = 0

u^2 = 0

u^2 = 0

1*u^2 = 0 // : 1

u^2 = 0

u = 0

u in (-oo:0) U (0:+oo)

3-(5*u)-((3*u^2)/(u^2))+4 = 0

3-5*u-3+4 = 0

4-5*u = 0 // - 4

-5*u = -4 // : -5

u = -4/(-5)

u = 4/5

u = 4/5

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